14 Nov
2015
14 Nov
'15
10:18 p.m.
Oliver Lehmann <lehmann(a)ans-netz.de> writes:
ldl rr2,rr8(#4)
ldl rr4,rr2
and r4,#32512
ldl _u+78,rr4
This looks like it could be:
u.u_dirp.l = uap->linkname;
u.u_dirp.left &= 0x7f00;
does the same but with more instructions and of course not 1:1
binary "the same" ;)
wonder why
u.u_dirp.l = (caddr_t)(((long)uap->linkname) & 0x7F00FFFF);
didn't worked.
Well, what code did it generate? Are longs in the same byte order as
pointers (could it have needed to be FFFF7F00)?