Re: [TUHS] Arithmetic expansion in Unix shells

even tho it was there, in-shell integer arithmetic had a few issues before ksh86. pre-ksh86 these had problems -- A. decimal point in a number $ integer I $ I=2.2 would error on the assignment, but with ksh86 $I is truncated to 2 (yes "integer" is an builtin alias to typeset -i and ksh courses at the time instructed to use that over typset) B. negative numbers $ integer I $ I=-2 here pre-86 $I would be assigned a large value like 2147483646 also ksh was not stardard until SVR4 (very late 80s) so it was found in paths like /usr/add-on/bin/ksh or /usr/exptools/bin/ksh, or not even there at all, you could not reliably #! ksh scripts also with ksh86 the double paren ((...)) notation was exactly the same as "let ..." and were completely optional if the variable was predefined as an integer, so $ I=0 $ ((I=I+1)) and $ integer I $ I=0 $ I=I+1 are the same. All internal integers in ksh were C longs (at least 32-bits) where Bourne shell all vars are strings so you would need to do this -- $ I=`expr $I + 1` But also at that time expr(1) could NOT deal with negative numbers on input, they became strings. So $ expr -9 + 1 is an error with "non-numeric argument", and $ expr -11 '<' -1 returns 0, a false statement, which are hidden bugs with variables. expr(1) was also 32-bits, as was test (i.e [ ) which could deal with negative numbers just fine. for arbitrarily large numbers you needed use dc(1) or bc(1). but dc(1) also has a issue with inputing negative numbers as it uses an _ not a - to denote a negatve number on input, but does use the - on output. $ I=`echo _9 1 - p | dc` is how you would do ((I=-9 - 1)) in bourne with dc which is cumbersome if you have a variable with a neagtive number in it, and required a "tr - _" first. however $ I=`echo -9 - 1 | bc` worked just fine in bourne. -Brian Chet Ramey wrote: