2 May
2008
2 May
'08
8:31 a.m.
On Fri, May 02, 2008 at 10:58:08AM +1000, Warren Toomey wrote:
On another note, I thought of taking V6 mkfs.c as a
start-point to rewrite
V1 mkfs.
I gave up and decided to write mkfs from scratch :-)
I'm a bit baffled on the i-node map and list. The V1 filesystem(5) manual says:
I-numbers below 41 (base 10) are reserved for special files, and
are never allocated; the first bit in the i-node free map refers
to i-number 41. Therefore the byte number in the i-node map for
i-node i is (i-41)/8 and offset (i-41)%8 bits from the right...
I-numbers begin at 1, and the storage for i-nodes begins at block 2.
Also, i-nodes are 32 bytes long, so 16 of them fit into a block.
Therefore, i-node i is located in block (i+31)/16 of the file system,
and begins 32*((i+31)%16) from its start.
I-node 41 (base 10) is reserved for the root directory.
Now, I am assuming that this means:
a) the i-mode bitmap is missing bits 0 to 40, but
b) the actual i-nodes 0 to 40 do exist, and
c) the system can still "read i-node 7", even if it can't allocate i-node
7.
Following the manual, the root directory i-node is number 41, so its
bit in the bitmap is (41-41)/8==0, offset (41-41)%8== bit 0. But the
actual i-node used is still i-node 41, so that is on block (41+31)/16==block4,
offset 256.
Let me know if that sounds right, or if I'm off-base somewhere.
Thanks,
Warren