2 Oct
2006
2 Oct
'06
9:24 p.m.
Yes...thank you for pointing out my typo and what does the back slash mean.
In the v6 assembler manual, the \> is listed as an example of
escaping, but it doesn't clearly state it equals to logical shift
right (or left).
Regards,
Qinglai
On 10/2/06, Jose R Valverde <txomsy(a)yahoo.es> wrote:
No.
On PDP 11 assembler the left and right shifts were a
single < and >.
You made a typo when transcribing the source
statement: you typed
0636: mov $USIZE-1/<8|6, (r1)+
but the actual code from m40.s reads
0636: mov $usize-1\<8|6,(r1)+
However, since < and > where also used to delimit
strings, there was a
need to escape them so as to distinguish their usage
as shifts from the
string delimiters. The escaping was achieved by \
which is what you see
in the code.
See the assembler section of vol 2b of the Unix V7
manuals for details at
http://plan9.bell-labs.com/7thEdMan/v7vol2b.pdf
or
http://web.cuzuco.com/%7Ecuzuco/v7/v7vol2b.pdf
namely:
6.1 Expression operators
The operators are:
(blank) when there is no operand between operands,
the effect is
exactly the same as if a ''+'' had appeared.
+ addition
– subtraction
* multiplication
\/ division (note that plain '' / '' starts a
comment)
& bitwise and
| bitwise or
\> logical right shift
\< logical left shift
... ... ...
j
On Mon, 2 Oct 2006 09:44:58 +0300
jigsaw <jigsaw(a)gmail.com> wrote:
hi all,
I just started to read the source code of V6 with
Lion's book.
>
> But before I went far I was stopped by m40.s
>
0636: mov $USIZE-1/<8|6, (r1)+
>
> What does the slash "/" stand for?
>
> I guess this line should be
>
> mov $USIZE-1<<8|6, (r1)+
>
> Is "/<" the same as "<<"?
>
> I checked in Unix PDP11 Assemble Refrence Manual but
didn't find a clue.
Is it the right place to ask such question?
Thanks in advance
Regards,
Qinglai
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