[TUHS] C declarations.

Ron Natalie ron at ronnatalie.com
Mon May 15 10:23:31 AEST 2017

It's a pointer.


Ø   Of course it is! But that doesn't mean that it SHOULD be, which is the point.


Actually, it is **Not a pointer**, it gets passed as a pointer, but it is an array on both ends.



The implicit conversion of the array name to a pointer to its first item is a different issue.   This bothers me less, but it’s still hokie in my opinion.



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