[TUHS] C declarations.

Ron Natalie ron at ronnatalie.com
Mon May 15 10:23:31 AEST 2017


It's a pointer.

 

Ø   Of course it is! But that doesn't mean that it SHOULD be, which is the point.

 

Actually, it is **Not a pointer**, it gets passed as a pointer, but it is an array on both ends.

 

 

The implicit conversion of the array name to a pointer to its first item is a different issue.   This bothers me less, but it’s still hokie in my opinion.

 

 

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